News

Inductance is calculated by the following formula: Description of the coil formula

Inductance is calculated as follows: coil formula
Impedance (ohm) = 2 * 3.14159 * F (operating frequency) * inductance (mH), set to use 360 ohm impedance, therefore:
Inductance (mH)=impedance (ohm)÷(2*3.14159)÷F(operating frequency)=360÷(2*3.14159)÷7.06=8.116mH
According to this, the number of windings can be calculated:
Number of turns = [inductance * {(18 * circle diameter (吋)) + (40 * circle length (吋))}] circle diameter (吋)
Number of turns = [8.116 * {(18 * 2.047) + (40 * 3.74)}] ÷ 2.047 = 19 ring hollow inductance calculation formula
Author: Anonymous Copy from: Site author Hits: 6684 article entry: zhaizl
Hollow inductance calculation formula: L(mH)=(0.08D.D.N.N)/(3D+9W+10H)
D------coil diameter
N------ coil turns
D-----wire diameter
H----coil height
W----coil width
The units are mm and mH respectively. .
Air core inductance calculation formula:
l=(0.01*D*N*N)/(L/D+0.44)
Coil inductance l unit: Wei Heng
Coil diameter D unit: cm
Coil number N unit: 匝
Coil length L unit: cm
Frequency inductance capacitance calculation formula:
l=25330.3/[(f0*f0)*c]
Working frequency: f0 unit: MHZ this question f0=125KHZ=0.125
Resonant capacitor: c unit: PF title definition c=500...1000pf can be decided by itself, or by Q
Value decision
Resonant inductance: l unit: Wei Heng
Calculation formula of coil inductance
Author: coil inductance calculation formula posted by: Reproduced Hits: 299
1. For the circular CORE, the following formula is available: (IRON)
L=N2. ALL = inductance value (H)
H-DC=0.4πNI/lN=number of turns of the coil (circle)
AL = inductance
H-DC=DC magnetizing force I=through current (A)
l = magnetic path length (cm)
l and AL value size, refer to the Microl comparison table.
The transformers shall meet the requirements specified in addition to the routine tests.
For example: with T50-52 material, the coil is 5 turns and half, and its L value is T50-52 (indicating OD is 0.5 inch). After checking the table, its AL value is about 33nH.
L=33. (5.5) 2 = 998.25nH ≒ 1μH
When 10A current flows, its L value can be changed by l=3.74 (check the table)
H-DC=0.4πNI/l=0.4×3.14×5.5×10/3.74=18.47 (after checking the table)
You can see the degree of decrease in L value (μi%)
2. Introduce an empirical formula
L=(k*μ0*μs*N2*S)/l
among them
00 is vacuum permeability = 4π * 10 (-7). (10 minus seven powers)
Ss is the relative magnetic permeability of the inner core of the coil, and μs=1 for the air-core coil
N2 is the square of the number of turns of the coil
S-coil cross-sectional area in square meters
l The length of the coil, in meters
The k factor depends on the ratio of the radius (R) of the coil to the length (l).
The unit of calculated inductance is Henry. k value table
2R/lk
0.10.96
0.20.92
0.30.88
0.40.85
0.60.79
0.80.74
1.00.69
1.50.6
2.00.52
3.00.43
4.00.37
5.00.32
100.2

PREVIOUS：Solenoid Terminology - IntroductionNEXT：What is an inductor? What is the inductance c