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How to make fast inductance and capacitance calculations

To make fast inductance and capacitance calculations, we need to understand what inductors and capacitors are. Inductance and capacitance are attributes of the energized circuit and are physical quantities.
Inductance means that the interaction between current and coil is called inductance. The unit is Henry (H).
Capacitance refers to a passive component of a storage container that has the characteristics of AC resistance and direct current, commonly indicated by the letter C.
Load its inductance as follows: coil formula
Impedance (ohm) = 2 * 3.14159 * F (operating frequency) * Inductance (mH), setting requires 360 ohm impedance, therefore:
Inductance (mH) = Impedance (ohm) ÷ (2*3.14159) ÷ F (operating frequency) = 360 ÷ (2*3.14159) ÷ 7.06 = 8.116mH
According to this, the number of windings can be calculated:
Number of turns = [inductance * { ( 18 * circle diameter (吋)) + ( 40 * circle length (吋))}] ÷ circle diameter (吋)
Number of turns = [8.116 * {(18*2.047) + (40*3.74)}] ÷ 2.047 = 19 laps
Capacitor power calculation formula:
P=1/2 * C * V2 * F
Inductance power calculation formula:
P=1/2 * L * I2 * F
The energy carried on the capacitor (Joules) is one-half the multiplied by the capacitance (Fara) and multiplied by the square of the capacitor voltage (volts).
There is a formula for calculating the silicon chip power: power = C (parasitic capacitance) * F (frequency) * V2 (square of the operating voltage). For the same core, C (parasitic capacitance) is a constant, so the silicon chip power is proportional to the frequency and proportional to the square of the operating voltage.
The 1 Farad 5V capacitor carries 12.5 joules of energy. 1 joule = 1 watt per second
The new 1.2 volt 1.8A nickel-metal hydride rechargeable battery is charged with 1.2*1.8*3600=7776 joules. In the current commercial environment, the volumetric energy ratio of the Ni-MH rechargeable battery to the Farad capacitor is 250:1, and the price ratio is 1:2. In addition, capacitor discharge requires a special constant voltage output adjustment circuit.
In the production design, circuit design or circuit test process, the inductance and the size of the capacitor are often calculated to adjust and improve the parameters. So learning how to calculate inductance and capacitance is a must.

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